Plot of l = 6, m = 3 spherical harmonic plotted as phase colours (red = 0, cyan = π) on the surface of a sphere.  There are m = 3 rainbows of colour going around the z axis. The l - |m| = 6 - 3 = 3 cone (θ) nodes may be seen in pink.  

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Magnitude squared of l = 6, m = 3 spherical harmonic plotted as a function of θ and ϕ and coloured according to phase. The three rainbows are perhaps easier to see, and the cones are now separating different pieces of the orbital. 

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Magnitude squared of the real combination `+`(`/`(`*`(`^`(Y__6(theta, phi), 3)), `*`(sqrt(2))), `/`(1, `*`(sqrt(2), `*`(`^`(Y__6(theta, phi), 3)))))plotted as a function of θ and ϕ and coloured according to phase. We have the same function of θ and therefore the same cone nodes, but instead of 3 rainbows we now have three vertical nodal planes (ϕ nodes). First picture has only the cones showing: 

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Next we add the vertical plane nodes: 

Plot_2d 

If we look down on this, we see that the xz plane is not a node. This means that this must be the cos(3ϕ) function, which results from adding the two spherical harmonics. 

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